Skip to Main Content

Grade 05 Mathematics - EC: M05.A-T.2.1.2

Grade 05 Mathematics - EC: M05.A-T.2.1.2

Continuum of Activities

Continuum of Activities

The list below represents a continuum of activities: resources categorized by Standard/Eligible Content that teachers may use to move students toward proficiency. Using LEA curriculum and available materials and resources, teachers can customize the activity statements/questions for classroom use.

This continuum of activities offers:

  • Instructional activities designed to be integrated into planned lessons
  • Questions/activities that grow in complexity
  • Opportunities for differentiation for each student’s level of performance

Grade Levels

5th Grade

Course, Subject

Mathematics

Activities

  1. Identify the quotient 100 ÷ 25 = 4

  2. In the equation 420 ÷ 70 = 6, what number represents the dividend?

  3. What is the name for the number 12 in the equation 60 ÷ 12 = 5?

  4. Define divisor.

  5.  12 ÷ 2 = ?
  1. Solve.  1020 ÷ 10
  1. Find the solution to 208 ÷ 4 =
  1. Is the solution correct?     8004 ÷ 4 = 201
  1. When 324 is divided by 8 the solution is 42.  True or false?
  1. Five hundred students are placed into 10 groups.  How many students in each group?
  1. 320 divided by what number is 16?
  1. How many groups will there be if 3,096 people are placed in groups of 12?
  1. 680/17 = ?
  1. Is 17 a solution to the expression?      714 ÷ 42
  1.  
  1. Andy and Keisha solved the division problem shown below using different methods.  One of them is correct.  Which one is correct?  Use a different method to demonstrate why you believe this person is correct.  Explain the error in the incorrect work.

  1. List the values for w that would make the solution to the following expression a whole number.  Explain your reasoning.       12w4 ÷ 12
  1. Explain how to solve the following problem and justify your reasoning.
         Kali is figuring out how many teams will be formed for the competition if she has 2,091 players and 17
         people on a team.
  1. Each letter in the expression below represents a single digit in a whole number.
                abbc  ÷ dc
    List the possible divisors for the expression if the following statements are true. Explain your reasoning.
  • All solutions to the expression are whole numbers.
  • In the set of whole numbers, the digit a is the second whole number.
  • b < a
  • c > 6
  • c and d are divisible by 2
  1. 854 ÷ 12 = 71.   Is 71 the solution to this equation? Justify your answer by showing the work for two different methods and explaining your thinking.

  2. What is the smallest digit that will make the quotient a whole number? Justify your solution.
    15a0 ÷ 15
  1. State a word problem that will model the expression below.  Explain what the solution means in terms of the problem.   124 ÷ 8

  2. Use the digits below to create a division problem with a 2-digit divisor and a 2-digit dividend with the largest possible quotient.   Digits can be used multiple times.  Explain your reasoning.
    4   8   3   1

Answer Key/Rubric

  1. 4

  2. 420

  3. divisor

  4. the number in a division problem by which another number is to be divided

  5. 6
  1. 102

  2. 52

  3. No

  4. False

  5. 50

  6. 20

  7. 258

  8. 40

  9. Yes

  10.  21
  1. Keisha’s method is correct. Explanations will vary.  Andy’s method is incorrect because in the last step he did not bring down the 9 and 9 divided by 9 is 1, hence the answer of 121.

  2. The digits 2 and 8 will produce whole number solutions.  Since 12 divides evenly into 1200, we only need to worry about w4 (the tens and ones place of the number 12w4).  12 divides evenly into 24 and 84.

  3.  2,091 ÷ 17     May use repeated subtraction or simply divide the total number of players by the number of people on a team.

  4. 28 and 48.  Explanations must have:  solution is a whole number so the two numbers in the expression must divide evenly; the second whole number is one so a=1; b6 and divisible by 2 so c = 8; d is divisible by 2 so d = 2 or 4 or 6 or 8; all numbers were tried for d to see which digit allowed for a whole number solution to the expression.

  5. No it is not because I got a remainder.  Student shows work for the division problem and perhaps a repeated addition or subtraction problem (multiple ways of showing this are possible)

  6. 0 because 1500 divided by 15 is 100, which is a whole number.

  7. Answers will vary.  Explanation must include what the answer means in terms of the word problem.

  8. 88 divided by 11.  Explanation must describe creating the largest 2-digit dividend and the smallest 2-digit divisor because this will yield the largest quotient.
Loading
Please wait...