Grade 05 Mathematics - EC: M05.B-O.1.1.1
Grade 05 Mathematics - EC: M05.B-O.1.1.1
Continuum of Activities
The list below represents a continuum of activities: resources categorized by Standard/Eligible Content that teachers may use to move students toward proficiency. Using LEA curriculum and available materials and resources, teachers can customize the activity statements/questions for classroom use.
This continuum of activities offers:
- Instructional activities designed to be integrated into planned lessons
- Questions/activities that grow in complexity
- Opportunities for differentiation for each student’s level of performance
Grade Levels
5th Grade
Course, Subject
Mathematics
Related Academic Standards / Eligible Content
Activities
- Circle the brackets in the expression. 9 ÷ 2[2- 3(1+3)]
- If parentheses and brackets are in a numerical expression, which is first for order of operations?
- Simplify. 2(3 + 5)
- What should be solved first in the following expression: 3[6 + 2(1 + 4)]
- How many possible solutions are there to the simplification of the expression? Why?
33 - 4 + 3(6 + 5) ÷ 5 - Circle the expression with the smallest value.
12 + 6(9 – 1) ÷ 12 9 + 3(2 + 5) ÷ 7 - Simplify the expression. 7 + [14 – 16 ÷ 8 + (9 ÷ 3)]
- What is the difference between the solution to the expression {[24 – 6(1+1)] + 6} ÷ [1 + (6 – 4)] and the same expression with the braces removed?
- Which expression has a greater value?
a. 15 x 4 – 10 ÷ 5 + 2
b. (15 x 4 – 10) ÷ 5 + 2
c. 15 x 4 – 10 ÷ (5 + 2)
d. 15 x 4 – (10 ÷ 5+ 2) - Roses are in bunches of 12 and tulips are in bunches of 6. There are 3 bunches of red roses and 4 bunches of white roses. There are 2 bunches of yellow tulips and 5 bunches of pink tulips. What expression represents the total number of flowers?
a. 12 + 3 + 4 + 6(2 + 5)
b. 12(3 + 4 + 6 + 2 + 5)
c. 12(3 + 4) + 6(2 + 5)
d. 12(3 + 4 + 2 + 5) + 6 - What number can be substituted for B so the expression has a value of 2?
{[36 – 8(5- 3)] + B} ÷ [7 + (24 ÷ 4)] - Place brackets in the expression so that the solution is 4. 24 – 6(1+1) ÷ 1 + (6 – 4)
- Use any combination of brackets, braces and parenthesis in the expression so the solution is 4. One parenthesis is already placed in the expression.
2 + 3 ( 4 – 3 ÷ 12 – 7 + 3
Answer Key/Rubric
- Student circles both [ and ]
- Parentheses
- 16
- 1 + 4
- One solution. The order of operations permits only one solution.
- Students circle: 9 + 3(2 + 5) ÷ 7
- 22
- The difference is 8.
With braces: {[24 – 6(1+1)] + 6} ÷ [1 + (6 – 4)] = 6
Without the braces: [24 – 6(1+1)] + 6 ÷ [1 + (6 – 4)] = 14.
- A
- C
- 6
- [24 – 6(1+1)] ÷ [1 + (6 – 4)]
- [2 + 3 (4 – 3)] ÷ (12 – 7) + 3